1894 MLB Doubles by Team
Every team's total, added up from its players' lines. Two-base hits
The Boston Beaneaters led all of MLB in doubles in 1894, with 272, 1 ahead of the Baltimore Orioles. The average across 12 MLB teams is 229.4.
Led all of MLB in 1894
Boston Beaneaters
133 games
272
Doubles
1 clear of Baltimore Orioles
| # | Team | League | G | 2B |
|---|---|---|---|---|
| 1 |
Boston Beaneaters
|
NL | 133 | 272 |
| 2 | Baltimore Orioles | NL | 129 | 271 |
| 3 |
 Chicago Colts
|
NL | 136 | 268 |
| 4 |
 Philadelphia Phillies
|
NL | 132 | 258 |
| 5 | Cleveland Spiders | NL | 130 | 241 |
| 6 |
 Brooklyn Grooms
|
NL | 135 | 231 |
| MLB average | 229.4 | |||
| 7 |
 Cincinnati Reds
|
NL | 134 | 228 |
| 8 |
 Pittsburgh Pirates
|
NL | 133 | 223 |
| 9 | Washington Senators | NL | 132 | 218 |
| 10 |
 New York Giants
|
NL | 139 | 199 |
| 11 | Louisville Colonels | NL | 130 | 173 |
| 12 |
 St. Louis Browns
|
NL | 133 | 171 |
A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.