1895 NL Winning Percentage by Team
Every team's total, added up from its players' lines. Wins per decision
The Baltimore Orioles led the NL in winning percentage in 1895, with .667, .021 ahead of the Cleveland Spiders. The average across 12 NL teams is .500.
Led the NL in 1895
Baltimore Orioles
131 games
.667
Winning Percentage
.021 clear of Cleveland Spiders
| # | Team | G | W-L% |
|---|---|---|---|
| 1 | Baltimore Orioles | 131 | .667 |
| 2 | Cleveland Spiders | 132 | .646 |
| 3 |
 Philadelphia Phillies
|
133 | .595 |
| 4 |
 Chicago Colts
|
133 | .554 |
| 5 |
 Boston Beaneaters
|
133 | .542 |
| 5 |
 Pittsburgh Pirates
|
134 | .542 |
| 7 |
 Brooklyn Grooms
|
133 | .539 |
| 8 |
 Cincinnati Reds
|
132 | .508 |
| 9 |
 New York Giants
|
132 | .504 |
| NL average | .500 | ||
| 10 | Washington Senators | 133 | .336 |
| 11 |
 St. Louis Browns
|
136 | .298 |
| 12 | Louisville Colonels | 132 | .269 |
A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.