1896 MLB Doubles by Team
Every team's total, added up from its players' lines. Two-base hits
The Philadelphia Phillies led all of MLB in doubles in 1896, with 234, 27 ahead of the Baltimore Orioles. The average across 12 MLB teams is 180.5.
Led all of MLB in 1896
Philadelphia Phillies
130 games
234
Doubles
27 clear of Baltimore Orioles
| # | Team | League | G | 2B |
|---|---|---|---|---|
| 1 |
Philadelphia Phillies
|
NL | 130 | 234 |
| 2 | Baltimore Orioles | NL | 132 | 207 |
| 2 | Cleveland Spiders | NL | 135 | 207 |
| 4 |
 Cincinnati Reds
|
NL | 128 | 204 |
| 5 |
 Chicago Colts
|
NL | 132 | 182 |
| MLB average | 180.5 | |||
| 6 | Washington Senators | NL | 133 | 179 |
| 7 |
 Boston Beaneaters
|
NL | 132 | 175 |
| 8 |
 Brooklyn Bridegrooms
|
NL | 133 | 174 |
| 9 |
 Pittsburgh Pirates
|
NL | 131 | 169 |
| 10 |
 New York Giants
|
NL | 133 | 159 |
| 11 | Louisville Colonels | NL | 134 | 142 |
| 12 |
 St. Louis Browns
|
NL | 131 | 134 |
A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.