1896 MLB Winning Percentage by Team
Every team's total, added up from its players' lines. Wins per decision
The Baltimore Orioles led all of MLB in winning percentage in 1896, with .698, .073 ahead of the Cleveland Spiders. The average across 12 MLB teams is .501.
Led all of MLB in 1896
Baltimore Orioles
132 games
.698
Winning Percentage
.073 clear of Cleveland Spiders
| # | Team | League | G | W-L% |
|---|---|---|---|---|
| 1 | Baltimore Orioles | NL | 132 | .698 |
| 2 | Cleveland Spiders | NL | 135 | .625 |
| 3 |
 Cincinnati Reds
|
NL | 128 | .606 |
| 4 |
 Boston Beaneaters
|
NL | 132 | .565 |
| 5 |
 Chicago Colts
|
NL | 132 | .555 |
| 6 |
 Pittsburgh Pirates
|
NL | 131 | .512 |
| MLB average | .501 | |||
| 7 |
 New York Giants
|
NL | 133 | .489 |
| 8 |
 Philadelphia Phillies
|
NL | 130 | .477 |
| 9 |
 Brooklyn Bridegrooms
|
NL | 133 | .443 |
| 9 | Washington Senators | NL | 133 | .443 |
| 11 |
 St. Louis Browns
|
NL | 131 | .308 |
| 12 | Louisville Colonels | NL | 134 | .290 |
A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.