1897 MLB Winning Percentage by Team
Every team's total, added up from its players' lines. Wins per decision
The Boston Beaneaters led all of MLB in winning percentage in 1897, with .705, .013 ahead of the Baltimore Orioles. The average across 12 MLB teams is .500.
Led all of MLB in 1897
Boston Beaneaters
135 games
.705
Winning Percentage
.013 clear of Baltimore Orioles
| # | Team | League | G | W-L% |
|---|---|---|---|---|
| 1 |
Boston Beaneaters
|
NL | 135 | .705 |
| 2 | Baltimore Orioles | NL | 136 | .692 |
| 3 |
 New York Giants
|
NL | 137 | .628 |
| 4 |
 Cincinnati Reds
|
NL | 134 | .576 |
| 5 | Cleveland Spiders | NL | 130 | .531 |
| MLB average | .500 | |||
| 6 |
 Pittsburgh Pirates
|
NL | 134 | .465 |
| 7 |
 Brooklyn Bridegrooms
|
NL | 136 | .462 |
| 8 | Washington Senators | NL | 133 | .462 |
| 9 |
 Chicago Colts
|
NL | 138 | .447 |
| 10 |
 Philadelphia Phillies
|
NL | 133 | .415 |
| 11 | Louisville Colonels | NL | 135 | .395 |
| 12 |
 St. Louis Browns
|
NL | 133 | .221 |
A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.