1938 MLB Doubles by Team

The Cleveland Indians led all of MLB in doubles in 1938, with 300, 2 ahead of the Boston Red Sox. The average across 30 MLB teams is 156.5.

Led all of MLB in 1938 Cleveland Indians 153 games

300 Doubles 2 clear of Boston Red Sox

#	Team	League	G	2B
1	Cleveland Indians	AL	153	300
2	Boston Red Sox	AL	150	298
3	St. Louis Cardinals	NL	156	288
4	New York Yankees	AL	157	283
5	Washington Senators	AL	152	278
6	St. Louis Browns	AL	156	273
7	Pittsburgh Pirates	NL	152	265
8	Cincinnati Reds	NL	151	251
9	Philadelphia Athletics	AL	154	243
10	Chicago Cubs	NL	154	242
11	Chicago White Sox	AL	149	239
12	Philadelphia Phillies	NL	151	233
13	Brooklyn Dodgers	NL	151	225
14	Detroit Tigers	AL	155	219
15	New York Giants	NL	152	210
16	Boston Bees	NL	153	199
	MLB average			156.5
17	Philadelphia Stars	NN2	68	82
18	Homestead Grays	NN2	52	80
19	Kansas City Monarchs	NAL	68	77
20	Pittsburgh Crawfords	NN2	49	61
21	Baltimore Elite Giants	NN2	47	56
22	Atlanta Black Crackers	NAL	54	49
23	New York Black Yankees	NN2	39	46
24	Memphis Red Sox	NAL	58	45
25	Chicago American Giants	NAL	65	42
26	Newark Eagles	NN2	52	35
27	Jacksonville Red Caps	NAL	23	22
28	Birmingham Black Barons	NAL	48	20
28	Indianapolis ABCs	NAL	38	20
30	Washington Black Senators	NN2	21	15

A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.