1946 MLB Doubles by Team

The Boston Red Sox led all of MLB in doubles in 1946, with 268, 3 ahead of the St. Louis Cardinals. The average across 28 MLB teams is 148.0.

Led all of MLB in 1946 Boston Red Sox 156 games

268 Doubles 3 clear of St. Louis Cardinals

#	Team	League	G	2B
1	Boston Red Sox	AL	156	268
2	St. Louis Cardinals	NL	156	265
3	Washington Senators	AL	155	260
4	Boston Braves	NL	154	238
5	Brooklyn Dodgers	NL	157	233
5	Cleveland Indians	AL	156	233
7	Chicago Cubs	NL	155	223
8	Philadelphia Athletics	AL	155	220
8	St. Louis Browns	AL	156	220
10	Detroit Tigers	AL	155	212
11	Philadelphia Phillies	NL	155	209
12	New York Yankees	AL	154	208
13	Chicago White Sox	AL	155	206
13	Cincinnati Reds	NL	156	206
15	Pittsburgh Pirates	NL	155	202
16	New York Giants	NL	154	176
	MLB average			148.0
17	Newark Eagles	NN2	64	94
18	Baltimore Elite Giants	NN2	58	88
19	Homestead Grays	NN2	58	77
20	Philadelphia Stars	NN2	56	65
21	New York Cubans	NN2	50	56
22	New York Black Yankees	NN2	46	42
23	Kansas City Monarchs	NAL	67	41
24	Cincinnati-Indianapolis Clowns	NAL	69	30
24	Cleveland Buckeyes	NAL	68	30
26	Chicago American Giants	NAL	80	20
27	Memphis Red Sox	NAL	76	14
28	Birmingham Black Barons	NAL	66	8

A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.