1996 MLB Triples by Team

The Minnesota Twins and the New York Mets shared the lead of all of MLB in triples in 1996, with 47. The average across 28 MLB teams is 30.5.

Led all of MLB in 1996 Minnesota Twins 162 games

47 Triples Tied with New York Mets

#	Team	League	G	3B
1	Minnesota Twins	AL	162	47
1	New York Mets	NL	162	47
3	Milwaukee Brewers	AL	162	40
4	Philadelphia Phillies	NL	162	39
5	Kansas City Royals	AL	161	38
6	Colorado Rockies	NL	162	37
7	Cincinnati Reds	NL	162	36
8	Toronto Blue Jays	AL	162	35
9	Chicago White Sox	AL	162	33
9	Los Angeles Dodgers	NL	162	33
9	Pittsburgh Pirates	NL	162	33
12	Texas Rangers	AL	163	32
13	Boston Red Sox	AL	162	31
13	St. Louis Cardinals	NL	162	31
	MLB average			30.5
15	Florida Marlins	NL	162	30
16	Baltimore Orioles	AL	163	29
16	Houston Astros	NL	162	29
18	Atlanta Braves	NL	162	28
18	New York Yankees	AL	162	28
20	Montreal Expos	NL	162	27
21	California Angels	AL	161	24
21	San Diego Padres	NL	162	24
23	Cleveland Indians	AL	161	23
24	Detroit Tigers	AL	162	21
24	Oakland Athletics	AL	162	21
24	San Francisco Giants	NL	162	21
27	Chicago Cubs	NL	162	19
27	Seattle Mariners	AL	161	19

A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.