1998 MLB Doubles by Team
Every team's total, added up from its players' lines. Two-base hits
The Boston Red Sox led all of MLB in doubles in 1998, with 338, 4 ahead of the Cleveland Indians. The average across 30 MLB teams is 291.4.
Led all of MLB in 1998
Boston Red Sox
162 games
338
Doubles
4 clear of Cleveland Indians
| # | Team | League | G | 2B |
|---|---|---|---|---|
| 1 |
Boston Red Sox
|
AL | 162 | 338 |
| 2 |
 Cleveland Indians
|
AL | 162 | 334 |
| 3 |
 Colorado Rockies
|
NL | 162 | 333 |
| 4 |
 Houston Astros
|
NL | 162 | 326 |
| 5 |
 Seattle Mariners
|
AL | 161 | 321 |
| 6 |
 Toronto Blue Jays
|
AL | 163 | 316 |
| 7 |
 Anaheim Angels
|
AL | 162 | 314 |
| 7 |
 Texas Rangers
|
AL | 162 | 314 |
| 9 |
 Detroit Tigers
|
AL | 162 | 306 |
| 10 |
 Baltimore Orioles
|
AL | 162 | 303 |
| 11 |
 Cincinnati Reds
|
NL | 162 | 298 |
| 12 |
 Atlanta Braves
|
NL | 162 | 297 |
| 13 |
 Oakland Athletics
|
AL | 162 | 295 |
| 14 |
 San Diego Padres
|
NL | 162 | 292 |
| 14 |
 San Francisco Giants
|
NL | 163 | 292 |
| 14 |
 St. Louis Cardinals
|
NL | 163 | 292 |
| MLB average | 291.4 | |||
| 17 |
 Chicago White Sox
|
AL | 163 | 291 |
| 18 |
 New York Yankees
|
AL | 162 | 290 |
| 19 |
 New York Mets
|
NL | 162 | 289 |
| 20 |
 Philadelphia Phillies
|
NL | 162 | 286 |
| 21 |
 Minnesota Twins
|
AL | 162 | 285 |
| 22 |
 Montreal Expos
|
NL | 162 | 280 |
| 23 |
 Florida Marlins
|
NL | 162 | 277 |
| 24 |
 Kansas City Royals
|
AL | 161 | 274 |
| 25 |
 Pittsburgh Pirates
|
NL | 163 | 271 |
| 26 |
 Tampa Bay Devil Rays
|
AL | 162 | 267 |
| 27 |
 Milwaukee Brewers
|
NL | 162 | 266 |
| 28 |
 Chicago Cubs
|
NL | 163 | 250 |
| 29 |
 Arizona Diamondbacks
|
NL | 162 | 235 |
| 30 |
 Los Angeles Dodgers
|
NL | 162 | 209 |
A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.